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The Cardinal Wiseman Catholic School

The Cardinal Wiseman Catholic School

Maths Challenge Answer

Challenge 1

The solution is as follows:

If Miss Baxter wins by 10m then she runs 100m in the time it takes Mr Hanman to run 90m. That means Miss Baxter runs 10m for every 9m Mr Hanman runs.

That means she when she has run 110m Mr Hanman will have run 99m.

Miss Baxter wins the race by 1m

 

 

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